length= 9 cm
width= 5 cm
height= 4 cm
the surface area of the given cuboid.
[tex]s.a = 2(lb + bh + lh)[/tex]
[tex]s.a = 2((9 \times 5) + (5 \times 4) + (9 \times 4))[/tex]
[tex]s.a = 2(45 + 20 + 36)[/tex]
[tex]s.a = 2 \times 101[/tex]
[tex]s.a = 202 \: {cm}^{2} [/tex]
therefore, the surface area of the given cuboid is 202 square centimeters.