given:
radius of small cone= 4 cm
radius of large cone= 6 cm
height of small cone= 4 cm
height of large cone= 20 cm
solution:
big:
[tex]v = \frac{1}{3} \pi {r}^{2} h[/tex]
[tex]v = \frac{1}{ 3} \times \pi \times {6}^{2} \times 20[/tex]
[tex]v = 753.98 \: {cm}^{3} [/tex]
small:
[tex]v = \frac{1}{ 3 } \pi {r}^{2} h[/tex]
[tex]v = \frac{1}{3} \times \pi \times {4}^{2} \times 4[/tex]
[tex]v = 67.02 \: {cm}^{3} [/tex]
frustum:
[tex]v = 753.98 - 67.02[/tex]
[tex]v = 686.96 \: {cm}^{3} [/tex]
