The time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.
The length of the path traveled by the body is known as the distance covered by the body.
Distance is a 1-dimensional phenomenon. its unit is a meter(m). The distance can be found by the product of velocity and time.
The given data in the problem will be
u is the initial velocity =20m/sec
t is the time =?
d is the distance =?
From the Newtons second law;
[tex]\rm F \triangle t = \triangle P \\\\ \triangle t = \frac{\triangle P }{F} \\\\ \triangle t = \frac{m(v_f-v_i)}{F} \\\\ \ \triangle t = \frac{2240 (0-20))}{8410} \\\\ \triangle t = 5.3 \ sec \\\[/tex]
The distance travelled before the car stop is,
[tex]\rm \triangle t = \frac{1}{2} (v_f+v_i)\traingle t \\\\ \traingle x = \frac{1}{2} (-20+0)5.3 \\\\\ \triangle x= -53.3 m \ west[/tex]
Hence,the time taken, and the distance travelled by the car before stop, will be 5.3 second and -53.3 m west.
To learn more about the distance, refer to the link;
brainly.com/question/989117
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