From her eye, which stands 1.69 meters above the ground, Sadie measures the angle
of elevation to the top of a prominent skyscraper to be 36º. If she is standing at a
horizontal distance of 275 meters from the base of the skyscraper, what is the height
of the skyscraper? Round your answer to the nearest hundredth of a meter if
necessary.

Respuesta :

The height of the skyscraper is 201.5 meters, if the angle of elevation to the top of a prominent skyscraper to be 36º

What is trigonometry?

Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have:

Angle of elevation = 36 degree

Horizontal distance of 275 meters from the base of the skyscraper

From the tan ratio:

tan36 = x/275

x = 275(tan36)

x = 199.79 meters

The height of the skyscraper = 199.79+ 1.69 = 201.48 ≈ 201.5 meters

Thus, the height of the skyscraper is 201.5 meters if the angle of elevation to the top of a prominent skyscraper to be 36º

Learn more about trigonometry here:

brainly.com/question/26719838

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