The average rate of change of the function, over the given interval is 2.
This question is incomplete, the complete question is:
What is the average rate of change of f(x) = 2x+10, if this function interval are x = -3 to x = 0.
The average rate of change of f(x) over the interval [a,b] is expressed as;
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Given that;
We substitute our values into the expression above.
[tex]\frac{f(b)-f(a)}{b-a}\\\\\frac{f(0)-f(-3)}{0-(-3)}\\\\\frac{[2(0)+10]-[2(-3)+10]}{0-(-3)}\\\\\frac{[10]-[-6+10]}{3}\\\\\frac{[10]-[4]}{3}=\frac{6}{3}=2[/tex]
Therefore, the average rate of change of the function, over the given interval is 2.
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