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Analysis of an unknown compound shows that it contains 1.04 grams K, 0.70 grams Cr, and 0.86 grams
O. Find the empirical formula of the compound.

A. K₂CrO4
B. KCrO2
C. KCRO
D. K₂CrO2

Respuesta :

Answer:

1

Explanation:

1.04/MM = 1.04/39.09 = 0.0266 potassium moles

0.7/MM = 0.7/52 = 0.0133 chromium moles

0.86/MM =0.86/16 = 0.05375 oxygen moles

divide all the moles number by the lowest

0.0266/0.0133=2

0.0133/0.0133=1

0.05375/0.133=4

so the empirical formula is K2CrO4

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