Respuesta :

fieryanswererft

Answer:

60 meter

Explanation:

[tex]\begin{tabular}{|c|c|c|c|} \cline{1-2} \multicolumn{2}{|c|}{\bf {SOH CAH TOA Formula's}} \\ \cline{1-2} \cline{1-2} \rm{sine rule} & sin(\theta) \sf = opposite/hypotenuse \\ \cline{1-2} \rm{cosine rule} & cos(\theta) \sf = adjacent/hypotenuse \\\cline{1-2} \rm{tan rule} & tan(\theta) \sf = opposite/adjacent \\ \cline{1-2}\end{tabular}[/tex]

Given following:

hypotenuse: 68 meter

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tan(θ) ratio = opposite/adjacent = 15/8

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To find ratio of hypotenuse (use Pythagoras theorem):

(hypotenuse)² = (adjacent)² + (opposite)²

(h)² = (8)² + (15)²

h² = 289

h = √289 = 17

The height of the kite above ground is the opposite size.

[tex]\sf real \ size = ratio \ size[/tex]

[tex]\sf \dfrac{height \ above \ ground}{hypotenuse} = \dfrac{opposite}{hypotenuse}[/tex]

[tex]\sf \dfrac{height \ above \ ground}{68} = \dfrac{15}{17}[/tex]

[tex]\sf {height \ above \ ground}= \dfrac{68(15)}{17}[/tex]

[tex]\sf {height \ above \ ground}= 60 \ m[/tex]

semsee45

Answer:

60 m

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

  • [tex]\theta[/tex] is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

The given scenario can be modeled as a right triangle (see attached diagram) where:

  • θ = angle the thread makes with the ground
  • hypotenuse = thread of the kite
  • side opposite the angle = the height of the kite above the ground

As we have been given the hypotenuse (thread) and the angle θ, and need to find the height (side opposite the angle), we can use the sine trigonometric ratio.

The angle θ has been given as a tan trigonometric ratio.  

[tex]\sf \textsf{Therefore, if }\tan \theta=\dfrac{15}{8} \textsf{ then } \cos \theta=\dfrac{8}{17} \textsf{ and } \sin \theta = \dfrac{15}{17}[/tex]

To calculate the height of the kite above the ground, substitute the values into the sine ratio formula and solve for height:

[tex]\implies \sin \theta=\sf \dfrac{height}{thread}[/tex]

[tex]\implies \sf \dfrac{15}{17}=\sf \dfrac{height}{68}[/tex]

[tex]\implies \sf height=\dfrac{15}{17} \cdot 68[/tex]

[tex]\implies \sf height=\dfrac{1020}{17}[/tex]

[tex]\implies \sf height = 60 \:m[/tex]

Therefore, the height of the kite above the ground is 60 m.

Learn more about trigonometric ratios here:

https://brainly.com/question/27933160

https://brainly.com/question/27803719

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