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How much heat is needed to vaporize 10.00 grams of water at 100.0°c? the latent heat of vaporization of water is 2,259 j/g. 22.59 j 1,000 j 2,269 j 22,590 j

Respuesta :

The correct option is:

The latent heat of vaporization of water is given by option D. 22,590J

Latent heat of vaporization:

Latent heat of vaporization is energy required to change 1 kg of liquid to gas at atmospheric pressure at its boiling point.

Also, Latent heat is the energy released or absorbed during a phase change.

Energy released during phase change is Exothermic process.

Whereas energy absorbed during phase change is Endothermic process.

Q=mL

Q= Latent heat

m= mass= 10 g

L= Latent heat of vaporization= 2,259 J/g

Putting the values in the above equation:

Q=10*2259

Q=22590 L

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