0.4 M is the molarity of the solution.
The molarity of solution can be calculated by : [tex]C_M[/tex] = [tex]n/V[/tex] where,
n is the no. of moles of solute([tex]KMNO_4[/tex]) and
[tex]V[/tex] is the volume of the solution in L.
Now,
No. of moles can be calculated by: Given mass/ Molar mass
Molar mass of [tex]KMNO_4[/tex] is 158.034 g/mole
No. of moles of [tex]KMNO_4[/tex] = 36.1 g / 158.034 g/mole = 0.228 (app.) moles
Molarity of solution = 0.228 moles /0.566 L = 0.4 mol/L or 0.4 M
Hence, the molarity of a solution where 36.1 grams of potassium permanganate is dissolved in enough water to make 0.566 L of solution is 0.4 M
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