The speed of the cat 5 m from the sidewalk is 7.42 m/s
What is speed:
The Newton's equation of motion:
here the cat falls from the height,
h = 40 m
since The cat is falling from rest
Initial velocity, u = 0 m/s
acceleration, a = g = 9.8 m/s^2
substituting values in eq.
40 = 0 + ( 9.8 t^2)
t^2 = 40 / 9,8
t^2 = 4.0814
t = 2.02 s
now when cat is 5 m from sidewalk
distance, S = 40 - 5 = 35 m from top
so,
35 = u*2.02 + 1/2 ( 9.8* 2.02^2 )
u = 15 / 2.02
u = 7.4257 m/s
The speed of the cat 5 m from the sidewalk is 7.42 m/s
Learn more about speed of object here:
https://brainly.com/question/18698268
#SPJ4