The equation of the function is f"(x) = 2x^2 - 3
The parent function is given as:
f(x) = x^4
When it is stretched vertically by a factor of 2, the rule is
f'(x) = 2f(x)
So, we have
f'(x) = 2x^2
When shifted down 3 spaces, the rule is
f"(x) = f'(x) - 3
So, we have:
f"(x) = 2x^2 - 3
Hence, the equation of the function is f"(x) = 2x^2 - 3
Read more about function transformation at:
https://brainly.com/question/13810353
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