The formula of the compound is [tex]$\mathrm{Cr}_{2} \mathrm{~S}_{3} \mathrm{O}_{12}$[/tex]
Salmon colored powder = 2.65 g
Chromium = 0.70 g
Sulfur = 0.65 g
Oxygen = 1.30 g
Molar mass = 392.2
Molar mass = gram / moles
Molar mass of chromium
= 0.70 / 0.0135
= 52
Molar mass of salmon
= 0.65 / 0.0203
= 32.06
Molar mass of oxygen
= 1.30 / 0.0813
= 16
Molecular formula = 392.2 / (Cr + 3 S + 12 O)
= 392.2 / (52.00 + (3 x 32.06 + 12 x 16.00) ≈ 1
So, The formula of the compound is [tex]$\mathrm{Cr}_{2} \mathrm{~S}_{3} \mathrm{O}_{12}$[/tex]
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