The distance between car B's original point and the point where car A and car B pass each other is 20 miles, given the speed of car A is twice the speed of car B, and they are 60 miles apart initially.
We assume the speed of car B to be x miles/hour.
Given car A going at twice the speed of car B, the speed of car A = 2x miles/hour.
When moving toward each other, the relative speed of the cars is the sum of their speeds.
Therefore, the relative speed = x + 2x miles/hour = 3x miles/hour.
The total distance between the cars is given as 60 miles.
Therefore, the time taken by car A and car B to reach the same point = 60/3x hours = 20/x hours.
Therefore, the distance from car B's original point and the point where car A and car B pass each other = Speed of car B*Time = x*(20/x) miles = 20 miles.
Therefore, the distance between car B's original point and the point where car A and car B pass each other is 20 miles, given the speed of car A is twice the speed of car B, and they are 60 miles apart initially.
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