The volume of HCl required is 23.89 mL
Calculation of volume:
The reaction:
[tex]HCl + NaOH \rightarrow NaCl + H_2O[/tex]
As HCl and NaOH react in 1 : 1 ratio.
Volume of NaOH= 718 mL
Concentration= 0.183M
Volume of HCl= ?
Concentration= 5.50M
Using the dilution formula:
[tex]M_1\times V_1(NaOH)= M_2\times V_2(HCl)[/tex]
[tex]0.183\times 718= 5.50 \times V_2\\V_2=\frac{131.394}{5.50} \\V_2 = 23.89 \,mL[/tex]
Therefore,
Volume of HCl required will be 23.89 mL.
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