A circular solenoid contains 100 turns of wire and carries a current of 2 A. Its radius is 1 cm and its length is 10 cm. Calculate the magnetic flux through one turn of the wire making the solenoid.

Respuesta :

The magnetic flux through one turn of the wire making the solenoid is 7.88*10^-7 T m^2.

B = unI

= 4pi*10^-7*(100/0.1)*2

= 0.00251 T

Therefore, Flux = B*Area

= 0.00251*pi*(0.01^2)

= 7.88*10^-7 T m^2

Magnetic flux is a measurement of the entire magnetic discipline which passes thru a given vicinity. It's far a useful device for helping describe the outcomes of the magnetic pressure on something occupying a given vicinity. The size of the magnetic flux is tied to the specific location chosen.

The SI unit of magnetic flux is the Weber (Wb). A flux density of 1 Wb/m2 (one Weber in keeping with rectangular meter) is one Tesla (T).

A magnetic subject describes a location in which a magnetic pressure may be felt. Magnetic flux describes how a good deal of magnetic discipline passes through a place.

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