The molarity of KOH is 0.2678 moles/L.
Molarity(M) = number of moles/ volume of solutions in liter.
Number of moles(n) = mass of the substance/Molar mass
The mass of Oxalic acid is 0.546g.
The molar mass of Oxalic acid [tex]H_{2}C_{2}O_{4}[/tex] is 90g (1*2+12*2+16*4=90)
The number of moles of Oxalic acid is,
n = 0.546/90
n = 0.006 moles
So, the number of moles of Oxalic acid is 0.006 moles.
The volume of KOH is 22.40mL = 22.40*1000 = 0.0224L
Therefore the molarity of KOH is,
M = number of moles/ volume of solutions in liter
M = 0.006/0.0224
M = 0.2678 moles/L
Therefore, the molarity of KOH is 0.2678 moles/L
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