-31.2 kJ is the work done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.
It is represented by the equation
W = PΔV
where,
W = Work done
P = Pressure
ΔV = Change in volume (V₂ - V₁)
Now put the values in above formula we get
W = PΔV
= 4.4 atm × (13 L - 83 L)
= 4.4 atm × (-70 L)
= -308 atm L
Now change L atm into J
= -308 × 101.3 J [L × atm = 101.3 J]
= -31200.4 J
= -31200.4 × 10⁻³ kJ
= -31.2 kJ
Thus from the above conclusion we can say that -31.2 kJ is the work done during a reaction in which the internal volume contracts from 83 L to 13 L against an outside pressure of 4.4 atm.
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