Respuesta :
The speed with which the ball must be thrown vertically from ground level to rise to a height of 50 m is 31.305 m/s.
Given values:
Maximum height reached from ground level, h_max = 50 m
Final velocity of the ball, v = 0 m/s
Calculation of initial speed of the ball:
Step 1:
Using Newton's third equation of motion, we get:
v² = u² + 2as
where, v is the final velocity of ball
u is initial velocity of the ball
a is acceleration of ball
s is the maximum height attained by the ball
Step 2:
Here, the acceleration of the ball will be given as:
a = -g
= -9.8 m/s²
where, g is acceleration due to gravity
Applying this value in above equation we get:
v² = u² - 2gh_max
Re-arranging above equation, we get:
u² = v² + 2gh_max
u =√(v² + 2gh_max)
Step 3:
Applying values in above equation we get:
u =√((0 m/s)² + 2(9.8 m/s²)(50 m)
=√980
= 31.305 m/s
Therefore, the speed with which the ball must be thrown from ground level is 31.305 m/s in order to reach a maximum vertical height of 50 m.
Learn more about kinematic equations of motion here:
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