3 roots are exist, since the polynomial is of third degree.
According to statement
This follows immediately from the zero product property: if ab=0, then either a=0 or b=0. We have3 roots are exist, since the polynomial is of third degree.
(9x+ 7)(4x +1)(3x+ 4) = 0
from which it follows that each of which admits only one solution.
AND
using the fundamental theorem of algebra, expanding we have a polynomial that is of third degree:
(9x+ 7)(4x +1)(3x+ 4) = 0
108x^3 + 255 x^2 +169x + 28 =0
The theorem states that a polynomial will have up to n distinct roots. In this case, it follows that there are exactly 3, since the solutions to the system above are all distinct.
So, 3 roots are exist, since the polynomial is of third degree.
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QUESTION
According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function? (9x + 7)(4x + 1)(3x + 4) = 0 1 root 3 roots 4 roots 9 roots
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