Respuesta :

genan

Answer:

[tex](2x+2)^{6} = 64x^{6} + 384x^{5} + 960x^{4} + 1280x^{3} + 960x^{2} + 384x + 64[/tex]

Step-by-step explanation:

Learn more about binomial theorem here: https://brainly.com/question/4114316

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Answer:

Please see below

Step-by-step explanation:

Looks like the error is in the exponentiation of 2x

You have only raised x to the power of (6-k) not [tex](2x)^{6-k}[/tex] ie the entire term 2x should be exponentiated

For example, for k = 0 we should get
[tex]\binom{6}{0}\left(2x\right)^{6-0}\cdot2^{0}=\frac{6!}{\left(6-0\right)!0!}\left(2x\right)^{6-0}\cdot2^{0}=64x^{6}[/tex]

For k= 1, we should get

[tex]\binom{6}{1}\left(2x\right)^{6-1}\cdot2^{1}=\frac{6!}{\left(6-1\right)!1!}\left(2x\right)^{6-1}\cdot2^{1}=384x^{5}[/tex]

Use the same correction in the other terms