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A certain disease has an incidence rate of 0.5%. The false negative rate on a test for the disease is 5%; the false positive rate is 5%. Compute the probability that a person who tests positive actually has the disease. (You may find it useful to construct a probability contingency table.)

The probability a person who tests positive actually has the disease is _______
.

Give your answer accurate to at least 3 decimal places.

Respuesta :

The probability of a person who tests positive actually having the disease is 0.091.

How to compute the probability?

The probability will be:

Positive Negative  

Disease 49.75 0.25 50

No diseases 497.5 9452.5 9950

total 547.25  

Let's take the total to be 10,000

0.5/100 × 10,000=50

10,000-50 = 9950

0.5/100 × 50 = 0.25 - disease negative

49.75 - no disease positive

Therefore, 5/100 × 9950=497.5-no disease positive. Therefore, no disease negative will be:

P(disease/ positive):

= 49.75/547.25

= 0.091

Therefore, the probability of a person who tests positive actually has the disease is 0.091.

Learn more about probability on:

https://brainly.com/question/24756209

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