Write the equation of the line that passes through (5, −2) and is perpendicular to y equals 5 thirds times x minus 3 period y equals negative 3 fifths times x plus 1 y equals negative 3 fifths times x plus 19 fifths y equals 3 fifths times x minus 5 y equals 5 thirds times x minus 31 thirds

Respuesta :

The equation of the line is: y = -3/5x + 1.

How to Write the Equation of a Line?

The slope (m) of two lines that lie perpendicular to each other are negative reciprocals.

Given, y = 5/3x - 3, the slope (m) of the line is 5/3. The negative reciprocal of 5/3 is -3/5.

Thus, the line that is perpendicular to it will have a slope (m) of -3/5.

Substitute m = -3/5 and (a, b) = (5, -2) into y - b = m(x - a):

y - (-2) = -3/5(x - 5)

y + 2 = -3/5x + 3

y + 2 - 2 = -3/5x + 3 - 2

y = -3/5x + 1

Thus, the equation of the line is: y = -3/5x + 1.

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Answer: A a aa a a a a a

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