Respuesta :
Given:
Ksp of BaSO4 = 1.1 * 10⁻¹⁰
To determine:
The solubility concentration of SO4²⁻ ions
Explanation:
BaSO4 ↔ Ba²⁺(aq) + SO4²⁻(aq)
Ksp = [Ba²⁺][SO4²⁻]
if 's' is the solubility of the ions then we have
Ksp = s²
s = √ksp = √1.1*10⁻¹⁰ = 1.05*10⁻⁵M
Ans: solubility of sulfate ions is 1.05*10⁻⁵ M
The solubility concentration of sulfate ions in the given saturated solution of BaSO₄ at 25°C is 1.05 × 10⁻⁵M.
What is Ksp?
Ksp is known as the solubility product sonstant which is equal to the product of the concentration of their constituent ions.
Given chemical reaction is:
BaSO₄ ⇄ Ba²⁺(aq) + SO₄²⁻(aq)
Let the solubility of the Ba²⁺ & SO₄²⁻ ions be x, and Ksp equation will be written as:
Ksp = [Ba²⁺][SO₄²⁻]
1.1 × 10⁻¹⁰ = x²
x = √1.1 × 10⁻¹⁰ = 1.05 × 10⁻⁵M
Hence option (a) is correct.
To know more about Ksp, visit the below link:
https://brainly.com/question/25134328
