The change in entropy of ammonia is 132.2 J/K.
Firstly calculating molar entropy by the formula -
∆S = ∆Hv/T, where ∆S is entropy, ∆Hv is heat of vaporization and T is temperature.
∆Hv = 23.4 × 10000
Performing multiplication
∆Hv = 23400 J/mol
T = -33.5 + 273
Performing subtraction
T = 239.5 K
Keep the values in formula to find molar entropy.
Molar ∆S = 23400 ÷ 239.5
Performing division
Molar ∆S = 97.7 J/mol K
∆S = molar ∆S × number of moles
∆S = 97.7 × (23/17)
Performing multiplication and division
∆S = 132.2 J /K
Hence, the entropy is 132.2 J/K.
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