Respuesta :
The percent yield of NH₃ for the reaction is 75%
Percent yield is the percent ratio of actual yield to the theoretical yield
The first thing that you need to do here is to calculate the theoretical yield of the reaction that is if the reaction has 100% yield then
The balanced chemical equation
N₂ + 3H₂ → 2NH₃
This tell you that every 1 mole of nitrogen gas that takes part in the reaction will consume 3 moles of hydrogen gas and produce 1 mole of ammonia and here that 1 mole of nitrogen gas react with 1 mole of hydrogen gas and since enough hydrogen gas to ensure that all moles of nitrogen gas can react
3 mole H₂ > 1 mole H₂
1 mole H₂×2 mole NH₃/3mole H₂ = 0.667 mole NH₃
So at 100% yield this represent the reaction thereotical yield
Now that reaction produced 0.50 moles of ammonia then this represent the reaction actual yield
In order to find the % yield you have to figure out how many moles of ammonia are actually produced for every 100 moles of ammonia that could theoretically be produced
Then 0.667 moles will produce 0.50 moles so you can say that
100 moles NH₃ in theory ×0.50 moles NH₃ actual/0.667 moles of NH₃ actual = 75 moles of NH₃
Therefore, you can say that the reaction has a percent yield equal to
%yield = 75%
Know more about nitrogen and hydrogen
https://brainly.com/question/24449769
#SPJ4
