Respuesta :
If each car in the parking has only one color , then the option which cannot be the probability that the selected car will be green is 0.6 , the correct option is (c) .
In the question ,
it is given that ,
total numbers of car in the parking lot = 200 cars
number of white cars = 50
number of red cars = 30
number of silver cars = 20
let the number of green cars be "x" ,
So , the number of green cars possible = 200 - 100 = 100
that means x ≤ 100 .
So , P(green) = x/200
Option(a)
p = 0.2 ,
So , x/200 = 0.2
x = 40
Option(b)
p = 0.1 ,
So , x/200 = 0.1
x = 20
Option(c)
p = 0.6 ,
So , x/200 = 0.6
x = 120
Option(d)
p = 0.5 ,
So , x/200 = 0.5
x = 100 ,
We can see that only option(c) gives the number of green cars as 120 , which is not possible .
Therefore , If each car in the parking has only one color , then the option which cannot be the probability that the selected car will be green is 0.6 , the correct option is (c) .
The given question is incomplete , the complete question
In a parking lot with 200 cars, 50 cars are white, 30 cars are red, and 20 cars are silver. one car will be selected at random from the parking lot. if each car in the parking has only one color, which of the following cannot be the probability that the selected car will be green ?
(a) 0.2
(b) 0.1
(c) 0.6
(d) 0.5
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