If h(x)=(fog)(x) then h'(3) = 12.
Given:
Let f and g be differentiable functions such that f(3)=5,g(3)=7,f'(3) = 13, g'(3) = 6,f'(7) = 2 and g'(7) = 0
h(x)=(fog)(x)
h(x) = f(g(x))
h'(x) = f'(g(x)) * g'(x)
h'(3) = f'(g(3) * g'(3)
= f'(7) * 6
= 2*6
= 12
Therefore If h(x)=(fog)(x) then h'(3) = 12.
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