two point particles one charge of 8x10^-9 and the other with charge -2x10^-9 are separated by 4m. the electric field midway between them is

The force per unit charge produced on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Let the electric filed due to change 8x10^-9 be E1.

Then,

E1 = k.q/r²

k = 9 x 10^9

q = 8x10^-9

r = 4/2 = 2 m

E1 = 9 x 10^9 x 8x10^-9 / 2²

E1 = 18 N/C

Similarly,

Let the electric filed due to change -2x10^-9 be E1.

Then,

E2 = k.q/r²

k = 9 x 10^9

q = -2x10^-9

r = 4/2 = 2 m

E2 = 9 x 10^9 x -2x10^-9 / 2²

E2 = 4.5 N/C

Thus, due to opposite nature of the charges, they net filed will be obtained by subtracting the filed.

E (total) = E1 - E2

E (total) = 18 - 4.5

E (total) = 13.5 N/C

Thus, the electric field midway between two point particles is 12.3 N/C.

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