A flotation device is in the shape of a right cylinder, with a height of 0.500m and a face area of 4.00m 2on top and bottom, and its density is 0.400 times that of fresh water. It is initially held fully submerged in fresh water, with its top face at the water surface.Then it is allowed to ascend gradually until it begins to float. How much work does the buoyant force do on the device during the ascent?

Respuesta :

4.11 Jules work does the buoyant force do on the device during the ascent.

What is energy?

Energy is ability to do to work. So here we know that the work is the integral of the force over distance. This is simply according to equation 7 32 So we can then he refer to the equation, uh, immediately, uh, before equation 14 7 And we can then say that the work is going to be equal to the integral of the density of the water multiplied by G a times negative.

The integral of the force over distance is called work. With reference to the equation that comes before, we can see that the work may be expressed as

W = ∫ρ water g A(-y)dy,

where y = 0 denotes the water's surface and +y denotes an upward direction. Let h = 0.500 m.

The integral's lower and higher limits are then, respectively, -h and yf, where

yf/h = -ρ cylinder/ρ water = -0.4000.

As a result of the integral, W = 1/2 ρ water g A h²(1 - 0.4² kJ) is obtained.

W = 4.11KJ

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