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A 50.0g thermometer is used to measure the temperature of 180 mL of water. The specific heat of the thermometer, which is mostly glass, is 750J/(kgK), and it reads 18.0 ∘C while lying on the table. After being completely immersed in the water, the thermometer's reading stabilizes at 79.6 ∘C. What was the actual water temperature before it was measured?

Respuesta :

The initial temperature of the water is T = 81.2 C

heat lost by water = heat gained by thermometer

Q_lost = Q_gain

m_w*S_w*dT = m_T*S_T*dT

S_w and S_T are the specific heat capacities of the water and thermometer respectively

m_w*4186*(T-78.2) = 50*10^-3*750*(78.2-18)

mass of water = density *volume = 1000*(180*10^-3*10^-3) = 0.18 kg

0.18*4186*(T-78.2) = 50*10^-3*750*(78.2-18)

The initial temperature of the water is T = 81.2 C

To learn more about the thermometer the link is given below:

https://brainly.com/question/13889224?

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