a 110.-g sample of copper (specific heat capacity 5 0.20 j/8c ? g) is heated to 82.48c and then placed in a container of water at 22.38c. the final temperature of the water and copper is 24.98c. what is the mass of the water in the container, assuming that all the heat lost by the copper is gained by the wate

Respuesta :

The mass of water is 231.71kg

What is specific heat capacity?

The specific heat capacity of a substance is the quantity of heat required to increase the temperature of a unit mass of substance by 1°C or 1k. It is measured in J/kg/K. It is denoted by c.

The quantity of heat required is expressed as H= mc∆k. where m is the mass and k is temperature.

From the law of calorimetry, heat lost = heat gained. The specific heat capacity of water and copper are 400J/kg/k and 4200J/kg/k

heat lost by copper = 110×400× ( 82.48-24.98)

= 44000× 57.5 = 2530000J

heat gained by water = m× 4200 × (24.98-22.38)

= 4200× 2.6×M = 10920m

therefore 2530000= 10920m

where m is the mass of water

m= 2530000/10920

m= 231.71kg

therefore the mass of the water is 231.71kg

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