The difference in energy between the two levels responsible for the violet emission line of the calcium atom at 422.7nm is 2.93 eV.
given that :
The photon wavelength , λ = 422.7 nm = 422.7 × 10⁹ m
the energy of photon is given as follows :
E = hc / λ
where
h = planck constant = 4.135 × 10⁻¹⁵eV.s
c = speed of the light = 3 × 10⁸ m/s
now, putting the values in the energy formula, we get :
E = hc / λ
E = ( 4.135 × 10⁻¹⁵eV.s × 3 × 10⁸ m/s ) / 422.7 × 10⁹ m
E = 2.93 eV.
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