Respuesta :

LammettHash
The work is equivalent to the dot product of the two vectors.

[tex]W=\mathbf F\cdot\mathbf r=\langle2,-1,-1\rangle\cdot\langle3,2,-5\rangle=6-2+5=9[/tex]
zohazoee

Answer:

[tex]W=9[/tex]

Step-by-step explanation:

applying the following formula

[tex]W=r.f[/tex]

here the dot indicates the dot product

then

[tex]W=(3i+2j-5k).(2i-j-k)[/tex]

taking dot product

[tex]W=3.2+2.(-1)+(-5).(-1)[/tex]

[tex]W=6-2+5[/tex]

[tex]W=9[/tex]