keewee
keewee
13-04-2014
Mathematics
contestada
solve for x of (8x+30)°(4x+18)°
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Lilith
Lilith
13-04-2014
[tex](8x+30) ^{o}+(4x+18)^{o} =180^{o}\\ \\ 8x+30 ^{o}+ 4x+18 ^{o} =180^{o}\\ \\12x +48^{o}=180^{o} \ \ |-48^{o}\\ \\12x +48^{o}-48^{o}=180^{o}-48^{o}\\ \\12x= 132^{o}\ \ /:12\\ \\x=\frac{132^{o}}{12}\\ \\x=11^{o} \\ \\ \\ Answer : C. 11 [/tex]
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