Answer:
The correct answer is option D
Step-by-step explanation:
The lateral area of pyramid is
[tex]l * \sqrt{(w/2)^2 + h^2} + w * \sqrt{(l/2)^2 + h^2} \\[/tex]
Where
[tex]l = 42 yd\\w = 42 yd\\h = 38 yd\\[/tex]
Substituting all these values in above equation, we get -
[tex]42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\ + 42 * \sqrt{(\frac{42}{2})^2 + 38^2 } \\\\= 2 * 42 * 43.41\\= 3647 yd^2\\[/tex]
