EM09
EM09
14-04-2014
Mathematics
contestada
Determine the second derivative of y=cosxtanx.
Thanks :)
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Аноним
Аноним
14-04-2014
[tex]f(x)=cosxtanx\\\\(cosxtanx)'=\left(cosx\cdot\frac{sinx}{cosx}\right)'=(sinx)'=cosx\\\\(cosx)'=-sinx\\\\f''(x)=-sinx\\\\\frac{\delta^2 f}{\delta x^2}=-sinx[/tex]
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