Answer: 4 <-60
A complex number in rectangular form is Z, where Z = a + bi.
In the given above 2-2(sqrt 3)i. In order to change it into polar form ( z= r (cos theta + i sin theta) ) or r < theta, we have to find r first.
r = |z| = sqrt ( a^2 + b^2)
= sqrt (2^2 + (-2 sqrt 3)^2)
= 4
then theta = arctan(b/a)
= arctan ((-2sqrt3)/2)
= -60 degrees
Polar form = 4 ( cos (-60) + i sin (-60))
= 4 < -60 degrees
