solve with quadratic formula 8x^2-9x-5=0

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14-04-2015
Mathematics

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solve with quadratic formula 8x^2-9x-5=0

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Panoyin Panoyin · Answer 1 · 2015-04-14T00:23:26+02:00

[tex]8x^{2} - 9x - 5 = 0[/tex]

[tex]x = \frac{-(-9) +/- \sqrt{(-9)^{2} - 4(8)(-5)}}{2(8)} [/tex]

[tex]x = \frac{9 +/- \sqrt{81 + 160}}{16} [/tex]

[tex]x = \frac{9 +/- \sqrt{241}}{16} [/tex]

[tex]x = \frac{9 +/- 15.524}{16} [/tex]

[tex]x = 0.5625 +/- 0.97025[/tex]
[tex]x = 0.5625 + 0.97025[/tex] [tex]x = 0.5625 - 0.97025[/tex]
[tex]x = 1.53275[/tex] [tex]x = -0.40775[/tex]