Given:
rate of effusion of Helium = 6 hours
Data needed:
Molar mass of hydrogen gas = 2 g/mol
Molar mass of helium gas = 4 g/mol
Assume:
Constant conditions such as temperature and pressure.
Required:
rate of effusion of Hydrogen gas
Solution:
To solve the problem, we can use the formula:
rate of effusion of A/ rate of effusion of B = (molar mass of B/molar mass of A)^1/2
substituting values,
rate of effusion of hydrogen gas/ 6 hours = (4 g/mol/2 g/mol)^1/2
rate of effusion of hydrogen gas = 8.5 hours
