The numeral 47 in base a represents the same number as 74 in base b. assuming both bases are positive integers, what is the least possible value of a+b written in base 10?

Respuesta :

Both numbers have to be at least in base 8, so the least value of a+b is 8+8=16.

Base number is the number of digits which have a system of counting to represent the numbers. The least possible value of a+b written in base 10 is 16.

Given information-

The base of both represent the same number. Thus,

[tex]4a+7=7b+4[/tex]

Base number

Base number is the number of digits which have a system of counting to represent the numbers.

Solving it for b,

[tex]\begin{aligned}\\ 7b&=4a+7-4\\ b&=\dfrac{4a+3}{7} \\ \end[/tex]

The value of 47 with base is a equivalent to 0. Therefore,

[tex]4a+7\overline =0 \\ [/tex]

Therefore the value of the a is,

[tex]4a\overline = 4\\ a\overline =1[/tex]

As the value of a is 1 with mod 7. Thus the smallest possible value of x can be 8.

As the value of a is 8 and the highest base value is 16. Thus a+b can only be less than or equal to 16.

If b has to written in base 10, thus the value of b must be less than 9. Hence the value of b is 8 which satisfy both the conditions. Thus,

[tex]a+b=8+8=16[/tex]

Therefore the least possible value of a+b written in base 10 is 16.

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