Respuesta :

External portion of the secant segment PN is x

PN = 32
LN = 22 + 14 = 36

By the Secant and Segment Theorem:
[tex]PN*x=LN*MN \\ 32x=36*14 \\ 32x=504 \\ x=504/32 \\ x=15.75 \ units[/tex]