The mean life of pairs of shoes is 40 months with a standard deviation of 8 months. if the life of the shoes is normally distributed, how many pairs of shoes out of one million will need replacement before 30 months? round your answer to the nearest integer.

Respuesta :

μ = 40
σ = 8
X (random variable) = 30
Let's calculate the Z score:

Z= (X-μ)/σ

Z= (30-40)/8; Z = - 1.25
Te corresponding area OF Z = - 1.25 is 0.1056
P(X<30) = 0.1056
Expected value  = P(X).(n) = (0.1056)(1,000,000)= 105,600