Denise2547 Denise2547

15-07-2017
Mathematics

contestada

Use these values to solve this problem. X=2,y=3,z=4. 21xy/x+z

Respuesta :

15-07-2017

21 x 2 x 3 / 2 + 4 = 126/6 = 21

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Nick911 Nick911

15-07-2017

x=2. y=3, z=4
21xy/x+z
Substitute x with 12, y with 3, z with 4
21xy/x+z
=21(2)(3)/(2+4)
=42(3)/16
=126/16
=21. As a result, 21 is your correct answer. Hope it help!

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