We will use the Binomial Probability formula to find the answer
The formula is given by ⁿCₓ (p)ˣ (1-p)ⁿ⁻ˣ
Where:
n, the number of trials = 5
x, the number of success that we aim = 2
p, the probability of success = 0.5 ⇒ there are six out of twelve numbers on the dice that are even
Substitute these values into the formula, we have
P(2) = ⁵C₂ (0.5)² (1-0.5)⁵⁻²
P(2) = ⁵C₂ (0.5)² (0.5)³
P(2) = 0.3125
