Respuesta :
x = 1st odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+ x+2 + x+ 4 = 3
3x+6 = 3
3x = -3
x= -1
so -1,1,3 are consecutive odd integers
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+ x+2 + x+ 4 = 3
3x+6 = 3
3x = -3
x= -1
so -1,1,3 are consecutive odd integers
consecutive odd numbers are 2 apart
so they are x, x+2,x+4
the sum is 3
x+x+2+x+4=3
3x+6=3
minus 6 both sides
3x=-3
divide 3
x=-1
x+2=1
x+4=3
the numbers are -1,1,3
so they are x, x+2,x+4
the sum is 3
x+x+2+x+4=3
3x+6=3
minus 6 both sides
3x=-3
divide 3
x=-1
x+2=1
x+4=3
the numbers are -1,1,3