Find the measure of an angle whose supplement is 10 degrees more than twice its compliment. Let 90-x equal the degree measure of its complement and 180-x equal the degree measure of its supplement. Write and solve an equation.
supplement is 10 more than twice compliement 180-x=10+2(90-x) solve distribute 180-x=10+180-2x 180-x=190-2x add 2x to both sides 180+x=190 minus 180 both sides x=10 degrees