Respuesta :
if I understand right you want the inverse of H(x)
H(x)=x
y=x
to calculate the inverse, isolate x, which is already the case, switch x and y, which doesn't change anything and that is your new function
the inverse is the same function in this case
so H⁻¹(x)=x
H(x)=x
y=x
to calculate the inverse, isolate x, which is already the case, switch x and y, which doesn't change anything and that is your new function
the inverse is the same function in this case
so H⁻¹(x)=x
Since it's H^-1(x), than just look at the H(x)=x section and do the following:
1) Substitute the x in the equation for the x from the H^-1(x) -
H(x)= (x)
2) Next take the x out of the parentheses cause there's nothing to multiply it to:
H(x)= x
3) x is your answer cause there's nothing else to do
Answer: x
outro; live