Respuesta :
[tex]\bf \begin{array}{llll}
x&\boxed{1}&3&\boxed{4}\\\\
y&\boxed{8}&6&\boxed{-1}
\end{array}\\\\
-------------------------------\\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 1}}\quad ,&{{ 8}})\quad
% (c,d)
&({{ 4}}\quad ,&{{ -1}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-8}{4-1}\implies \cfrac{-9}{3}\implies -3[/tex]
Answer:
The slope between the points where x=1 and where x=4 is :
-3
i.e. option: A is the correct answer.
Step-by-step explanation:
Let Y=f(X)
We are given a table of values as:
X: 1 , 3 , 4
Y: 8, 6, -1
Let m represents the slope .
We know that the slope between the points x=a and x=b is give by:
[tex]m=\dfrac{f(b)-f(a)}{b-a}[/tex]
Here we are asked to find the slope between x=1 and x=4
i.e. we have:
a=1 and b=4
f(a)=8 and f(b)= -1
Hence, the slope between x=1 and x=4 is calculated as:
[tex]m=\dfrac{-1-8}{4-1}\\\\m=\dfrac{-9}{3}\\\\m=-3[/tex]
Hence, the slope is:
-3