First let us assume all black cards, the numbers that will result in 24 is:
2 * 12
3 * 8
4 * 6
Similar case with the red cards:
-2 * -12
-3 * -8
-4 * -6
Assuming the product can be negative, so we can also take the combination of two cards (1 red and 1 black):
2 * -12
3 * -8
4 * -6
-2 * 12
-3 * 8
-4 * 6
So there are a total of 12 combinations.
Answer: There are 6 possible combinations of cards Jamal could use.
Step-by-step explanation:
Since we have given that
There are 2 cards:
1) Black cards
2) Red cards
Red cards are represented as negative numbers and black cards are represented as positive numbers.
We need a product of 24.
So, According to black cards , we get product in these combinations:
[tex]12\times 2\\\\8\times 3\\\\6\times 4[/tex]
According to red cards, we get product in these combinations:
[tex]-12\times -2=24\\\\-6\times -4=24\\\\-3\times -8=24[/tex]
Hence, there are 6 possible combinations of cards Jamal could use.
