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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the distance in 4 h. Car A traveled 22 mph faster than Car B. How fast did Car A travel? (The formula R⋅T=D , where R is the rate of speed, T is the time, and D is the distance can be used.)

Respuesta :

coolstick
If Car A's speed is x, then Car B's speed is x-22. Using the formula, we get that the distance is the same in both, so 4*(x-22)=D and 2.4*x=D due to that we plug 2.4 and 4 in for T and x-22 and x for R. Since they both equal D, we can write it as 2.4*x=4*(x-22). Using the distributive property, we get 4*(x-22)=4x-88=2.4*x. Subtracting 2.4*x from both sides as well as adding 88, we get 1.6*x=88. Dividing both sides by 1.6, we get 88/1.6=55= x=Car A's speed
dreadonut2007

Answer: 55mph

If no one understood the explanation above, 55mph is the answer.

Also please give your hearts and stars to the person above for answering the equation. I just wanted to clarify for people who don't understand. <3

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